|
Post by folk_singers_r_ on Dec 31, 2010 4:17:30 GMT
Maryyy was working in a chemistry lab with a mixture of chemicals that was 90% water and weighed 20 pounds. After returning to the lab from a weekend break, she calculated the mixture was now 50% water. How much does the mixture now weigh? For purposes of this problem, assume the non-water part of the mixture was not affected by evaporation.
Ill be back in 3 hours to check for the answer
thanks
|
|
|
Post by Thuada Gurjit Paji on Dec 31, 2010 5:33:43 GMT
I'll see if I can get an answer for u
But no offense this shouldn't be in the music section bro
|
|
|
Post by Thuada Gurjit Paji on Dec 31, 2010 7:34:23 GMT
around 10-11lbs
|
|
|
Post by $ukhjit on Dec 31, 2010 14:48:41 GMT
LOL, a new low for this forum. Is this the future of Punjab2000?
|
|
|
Post by -GT- on Dec 31, 2010 16:45:55 GMT
LOL...
|
|
|
Post by bedroomdj on Dec 31, 2010 19:16:58 GMT
LOL, a new low for this forum. Is this the future of Punjab2000? bhahahaha!! lol exalt! 50% would be 10pounds so your looking at a figured between 10 and 11 lbs - i.e. 10.5 lbs
|
|
|
Post by desidaku on Dec 31, 2010 21:19:30 GMT
great, that punjabiincarcererated f@gs back, schools not even in session because of winter break u idiot, so i dont know why your asking for help on hw problems
|
|
|
Post by folk_singers_r_ on Dec 31, 2010 22:42:00 GMT
these problems are part of my winter break math assicgnment
i told my mom the 10 lb answer and shes says your friends are wrong
she said
"10% of 20 lbs is 2 lbs, therefore when the water evaporates down to 50% of mixture, assuming the other chemicals stay at 2 lbs, the other 50% water, should also weigh 2 lbs, so the answer is 4lbs you jerkoffs ( her words not mine)"
|
|
|
Post by gSINGHg on Dec 31, 2010 23:16:23 GMT
hmmm and maybe you didnt realise but this isnt a mathematics forum, only complete idiots would have a query such as yours on a bhangra music forum
|
|
|
Post by hotelsierrabravo on Jan 1, 2011 4:55:06 GMT
these problems are part of my winter break math assicgnment i told my mom the 10 lb answer and shes says your friends are wrong she said "10% of 20 lbs is 2 lbs, therefore when the water evaporates down to 50% of mixture, assuming the other chemicals stay at 2 lbs, the other 50% water, should also weigh 2 lbs, so the answer is 4lbs you jerkoffs ( her words not mine)" Neither your mum or TGP are correct. The non-water part could weigh more than 2 lb's at first due to its density. We aren't given the weight or densities of either liquid in scenario 1, therefore you cant find the answer. If the densities were equal then your mum would be correct!
|
|
|
Post by folk_singers_r_ on Jan 1, 2011 19:53:51 GMT
these problems are part of my winter break math assicgnment i told my mom the 10 lb answer and shes says your friends are wrong she said "10% of 20 lbs is 2 lbs, therefore when the water evaporates down to 50% of mixture, assuming the other chemicals stay at 2 lbs, the other 50% water, should also weigh 2 lbs, so the answer is 4lbs you jerkoffs ( her words not mine)" Neither your mum or TGP are correct. The non-water part could weigh more than 2 lb's at first due to its density. We aren't given the weight or densities of either liquid in scenario 1, therefore you cant find the answer. If the densities were equal then your mum would be correct! dear frend, I talked to my momm about what you said she says for you to read the problem again she says the problem clearly states that the total weight is konstant at 20 lbs (9.071847400000001 kg), 90% of which is H2O (90% of 20 lbs = 18 lbs H2O, 20 lbs (total)- 18 lbs (H20) = 2lbs Non H2O chemicals that do not evaporate. Hence the Non H2O portion of the mixture is constant at 2 lbs. Therefore the densities do not come into play. please give your repsonspose cuz I really want to put down the right answer. Ill tell my mom wahtever u tell me, shes in the shower right now though, so it might takea wile
|
|
|
Post by hotelsierrabravo on Jan 2, 2011 2:33:39 GMT
Neither your mum or TGP are correct. The non-water part could weigh more than 2 lb's at first due to its density. We aren't given the weight or densities of either liquid in scenario 1, therefore you cant find the answer. If the densities were equal then your mum would be correct! dear frend, I talked to my momm about what you said she says for you to read the problem again she says the problem clearly states that the total weight is konstant at 20 lbs (9.071847400000001 kg), 90% of which is H2O (90% of 20 lbs = 18 lbs H2O, 20 lbs (total)- 18 lbs (H20) = 2lbs Non H2O chemicals that do not evaporate. Hence the Non H2O portion of the mixture is constant at 2 lbs. Therefore the densities do not come into play. please give your repsonspose cuz I really want to put down the right answer. Ill tell my mom wahtever u tell me, shes in the shower right now though, so it might takea wile This question is incomplete or is a trick quesiton, there are a few ways to go about it.. 1. Your mums, it would be 4lbs. Only if 90% is in regard to the weight of H20 and not volume, if it is volume we require more information. Were not told which one it is, see 3. 2. if 90% H20 = 18lb and 10% of X = 2lb, then reduction of 90% to 50% = new weight of 10lb .. 10lb + 2lb = 12lb <- This is wrong and so is the answers TGP & bedroomdj gave. the original H20 reduces so it is now in 1:1 (50% 50%) ratio with non-H20 i.e. water is now evaporated to 10% of original total (equal to the 10% of non-H20). 90% drop to 10% = 18 - 16 = 2 lb. Answer is 2 + 2 = 4lb. This is same as what your mum is saying, see 3. 3. Not enough information is given and we do not know if the 90% is in regard to the volume of H20 or the mass/weight of H20. 4. This is a trick question !!!
|
|
|
Post by hotelsierrabravo on Jan 2, 2011 2:37:09 GMT
|
|
|
Post by folk_singers_r_ on Jan 3, 2011 1:49:50 GMT
oh my god its due tomarrow morning in second paeriod and you dont even carrreeeee
|
|
|
Post by desidaku on Jan 3, 2011 2:59:44 GMT
thats a pretty good song, i like the beat but it seems kind of repetitive, not a bad try though for a first timer
|
|